But the intention of the programmer is usually to get three characters from the user, which is what is happening, isn’t? Let me explain. Usually, this happens inside a loop, but let’s see a sample code without a loop that exposes the problem.Īs you see, the input No.2 was skipped. Quite often I see the following problem in people’s code ( as a matter of fact, aliens don’t do that mistake :p ), when trying to input a character again and again with scanf. Tic Tac Toe Object Oriented Programming C++.Crosssection with traffic lights Object Oriented Programming.Create Pointset on a Sphere or a Klein bottle.Spark – Container exited with a non-zero exit code 143.Proper position in front of the computer.

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I have spent a lot of my spare time reading your content. I must admit that your post is really interesting. We are skipping this and reading only the provided char by inserting a space before %c.

This means that %c without a space will read as a white space, just like a new line, a space, or a tab. White space is eliminated with space before %c. So, by giving space before %c, we are skiping that white space and taking the char only. E.g.- in scanf(“%d%c“), we will hit ENTER or SPACE after giving integer value, so %c (without space) will match that white space (ENTER or SPACE) and not the char given after it (%d will take only numeric part and not the white space).

So, the conclusion is : We require space before %c to skip the white space in buffer memory.

Codeblocks compiler scanf not working